a person standing between two cliffs hitting drum at rate 120 beats per minute.if the sound of first beat concide with third and fifth beat then distance between two cliffs is(speed of sound is 360m/s)
Answers
The distance between the two cliffs is 540 m
Explanation:
Given that
A person produces 120 beats per minute
Therefore, in 1 second, the beats produced = 2
Thus, one beat is produced in 0.5 seconds
Third beat will be produced after 1 second
Fifth beat will be produced after 2 seconds
Distance travelled by sound in 1 second = 360 m
Which is twice the distance of the person from the first cliff
Therefore, distance between the person and first cliff = 360/2 = 180 m
Similarly,
Distance travelled by sound in 2 seconds = 360 × 2 m
Therefore, distance between the person and second cliff = 360 × 2/2 = 360 m
Thus, distance between the cliffs = 180 + 360 = 540 m
Hope this answer is helpful.
Know More:
Q: A person stands between two cliffs at distance d1 and d2 respectively. He claps every 2 seconds . The third clap coincide with the echo of first clap. If the speed of the sound is 360 m/sec, find d2-d1 .
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