A person standing between two vertical cliffs and 480m from the nearest cliff [3] shouts. He hears the first echo after 3s and the second echo 5s later. Calculate : the speed of sound and the distance of the outer cliff from the person.
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(i) Total distance travelled by the sound in going and coming back (in the case of the nearest cliff) =2×480 m
Speed of sound =
Timetaken
Totaldistancetravelled
=
3
2×480
=320m/s
ii)Time taken to reach second echo=3+2=5 s
Now v=
t
2d
⇒ d=
2
vt
Distance of the other cliff from the person =
2
320×5
=800m.
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