Question

A person standing in a stationary lift drops a coin from a certain height h. It takes time t to reach the floor of the lift. If the lift is rising up with a uniform acceleration a, the time taken by the coin, dropped from the same height h, to reach the floor will be

Answer 1

t=m(g-a)
t/m=g-a
g-t/m =a
$a = g - \frac{t}{m}$

Answer 2

The answer is 1/√8 s