Question

A person standing in between two parallel cliffs, fires a gun. He
hears the first echo after 2 sec and next echo after 6 sec. What is
the distance between two cliffs? Velocity of sound in air is 350
m/s. pls hurry ​

Answer 1

Answer:

Distance of person from nearer cliff, (d1​)

=2v×t​⇒d1​=2330×3​=495m

Distance of person from farther cliff, d2​=2v×t​

d2​=2330×5​=825m

Total distance between two cliffs

=d1​+d2​

=(495+825)

=1320m.

Explanation:

Answer 2

Explanation:

here you go thank you