Question

A person standing inside a rectangle form abcd and measures his distance from 3 of the corners as pa=10,pb=3,pc=6 what is his distance in meter from the other corner d

Answer 1

All are cyclic points.

Hence we will use cyclic points formula shown in attachment.

Answer 2

Answer:

Step-by-step explanation:

PA^2 + PC^2 = PB^2 + PD^2

10^2 + 6^2 = 3^2 + PD^2

100 + 36 = 9 + PD^2

PD^2 = 136 - 9

PD^2 = 127

PD = sqrt(127)