A person standing near the edge of the top of a building throws two balls A and B. the ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed vA and the ball B this the ground with a speed vB. We have
(a) vA > vB
(b) vA < vB
(c) vA = vB
(d) the relation between vA and vB depends on height of the building above the ground.
Answers
Answered by
2
Answer:
(a) vA > vB
Explanation:
(a) vA > vB
Similar questions
Math,
6 months ago
India Languages,
6 months ago
Physics,
6 months ago
Math,
1 year ago
Science,
1 year ago