A person standing on a tall building at height 360 m from the ground . From the same height , if the person holding a feather and a ball , release them in same time and same height from the building .
i) Find the time taken by the ball and the feather to reach the ground? (ignoring air resistance) Don't give any irrelevant answer
Answers
Answer:
Imagine an object body is falling freely for time t seconds, with final velocity v, from a height h, due to gravity g. It will follow the following equations of motion as: h= \frac{1}{2}gt^2. v²= 2gh.
Given : height 360 m from the ground
a feather and a ball is released from the same height
ignore air resistance
To Find : time taken by the ball and the feather to reach the ground
Solution:
As air resistance is ignored hence only force acting is gravitational force
Hence Acceleration for both will be g
S = ut + (1/2)at²
S = 360 m
u = 0 as released (dropped)
a = g = 9.8 m/s²
360 = 0 + (1/2)9.8 t²
=> t² = 3600/49
=> t = 60/7 sec
=> t = 8.57 secs
Both will take same time reach to ground 60/7 sec or 8.57 secs
Learn More:
A particle is dropped from a height of 80m . Find the distance ...
brainly.in/question/11370407
A ball is dropped from a height of 80ft the ball is such that it ...
brainly.in/question/11471174