Physics, asked by amarsaikia173, 10 hours ago

A person standing on a tall building at height 360 m from the ground . From the same height , if the person holding a feather and a ball , release them in same time and same height from the building .

i) Find the time taken by the ball and the feather to reach the ground? (ignoring air resistance) Don't give any irrelevant answer ​

Answers

Answered by MihirRanjanKar
2

Answer:

Imagine an object body is falling freely for time t seconds, with final velocity v, from a height h, due to gravity g. It will follow the following equations of motion as: h= \frac{1}{2}gt^2. v²= 2gh.

Answered by amitnrw
0

Given :  height 360 m from the ground

a feather and a ball is released from the same height

ignore air resistance

To Find :  time taken by the ball and the feather to reach the ground

Solution:

As  air resistance is ignored hence only force acting is gravitational force

Hence Acceleration for both will be g

S = ut + (1/2)at²

S = 360 m

u = 0   as released (dropped)

a = g  = 9.8 m/s²

360 = 0 + (1/2)9.8 t²

=>  t² = 3600/49

=> t  = 60/7 sec

=> t = 8.57 secs

Both will take same time reach  to ground 60/7 sec or 8.57 secs

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