A person standing on the bank of a river observes that the angle of elevation of the top of a tree on the opposite bank is 45°. When he moves 20m away from the bank, he finds the angle of elevation to be 30°. Find the height of the tree
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Let CD be the tree of height h m. Let B be the position of a man standing on the opposite bank of the river. After moving 40 m away from point B let new position of man be A i.e., AB = 40 m. The angles of elevation of the top of the tree from point A and B are 30° and 60° respectively, i.e., ∠CAD = 30° and ∠CBD = 60°.
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