A person standing on the floor of an elevator drops a coin
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A person standing on the floor of an elevator drops a coin. The coin reaches the floor of elevator in time t1 . If elevator is stationary and in time t2 if it is moving uniformly then a) t1 = t2 b) t1< t2 c) t1 >t2 d) t1 = t2/2.This is the whole ques.
utkarshbp9w5fg:
And the answer is t1=t2 bcz when lift is moving uniformly accelration is zero.hence no change in accelration of coin,therefore tym taken in both the situation will be same
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answer:
a) t1 = t2
explanation:
The stationary and uniformly moving elevator are both inertial frame so value of acceleration due to gravity will remain the same in both conditions. The distance traveled by the coin with respect to the frame of elevator is equal in both cases. So the time taken will also be equal.
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