Question

a person standing on top of a 25m height building throws a ball upwards at a speed of 20 m/s.find the time ball will take to come down​

Answer 1

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Correct option is

Time to reach maximum height can be obtained from v = u + at

0 = 20 + (-10)t

t = 2s

s = ut + 0.5at² = 20(2) +

0.5(-10) (2)² = 20m

Thus, total distance for maximum height is 45 m

s = ut + 0.5at²

45 = 0 + 0.5 (10) (t')²

t' = 3s

Total time= 3+2= 5s

A t=5s