Question

A person stands 40 m from a flag pole. the angle at the top of the flag pole with the horizontal at eye is 25o . what is the height of the flag pole, if the distance between the eye of the person to his feet is 1.8 m?

Answer 1

the way to solve it is by using tan25=a/40, then a=40*tan25=18.65m, 18.65m+1.8m=20.45m. so the answer is 20.45m

Answer 2

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$tan25 = \frac{a}{40}$

so

$a = 40 \: \: tan 25 = 18.65m$

so total height of flagpole is

18.65m+1.8m=20.45