Question

A person stands at the middle point of a wooden ladder which starts slipping between a vertical wall and the floor of a room, while continuing to remain in a vertical plane. The path traced by a person standing at the middle point of the slipping ladder is :

Answer 1

Answer:

so what's the question.

Answer 2

Circular path

Step-by-step explanation:

Suppose the wall is represented by the y-axis and the ground as the x-axis. Let the position of the man be given by M = (x, y).

Then,

since M is the midpoint of the ladder, the base of the ladder is at A = (2x, 0).

also, the point where it touches the wall is B = (0, 2y).

Now, AB is the length of the ladder so AB = constant.

Using Pythagoras's theorem,

(2x - 0)² + (0 - 2y)² = c

(2x - 0)² + (2y - 0)² = c

This is the equation of [a quadrant of] a circle with centre (0, 0) and radius = √c

hence , The path traced by a person standing at the middle point of the slipping ladder is circular

#Learn more :

Will the ladder slip if we add the weight of a person?

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