Question

A person stands in between two parallel cliffs & fires a gun.
He hears two successive echoes after 2 sec and 4.5 sec. Calculate the distance between the cliffs.​

Answer 1

Distance of person from nearer cliff, (d

1

)

=

2

v×t

⇒d

1

=

2

330×3

=495m

Distance of person from farther cliff, d

2

=

2

v×t

d

2

=

2

330×5

=825m

Total distance between two cliffs

=d

1

+d

2

=(495+825)

=1320m.

Note-googled it

Source-google

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