Question

a person start walking in east direction and walks 20m .after that he turns to his right and walks 10m and then turn to his left ans walks 15 m and reached at a ponit A. find the distance between A and initial point ???

Answer 1

After we draw the given question, we can find point A, the starting point and the point which is exactly 10m east of starting point forming a right angle triangle. So,

=√(10²+35²)

=√(100+1225)

=√1325

Answer 2

Concept

Pythagoras' Theorem states that the square of the hypotenuse side in a right-angled triangle is equal to the sum of the squares of the other two sides. The triangle's three sides are known as the perpendicular, base, and hypotenuse. Due to its position opposite the 90° angle, the hypotenuse, in this case, is the longest side. When the positive integer sides of a right triangle (let's say sides p, q, and r) are squared, the result is an equation known as a Pythagorean triple.

Given

Given that the person walks 20 m in the east direction, then 10 m to his right, and finally 15 m to his left to reach point A.

Find

We have to find the distance between A and the initial point.

Solution

Here, we can find the distance between A and the initial point by drawing a right-angled triangle. Let O be the initial point and we get the triangle OEA.

Here, the perpendicular of OEA = OE = 10

The base of OEA = EA = 20 + 15 = 35

So, the distance between A and O = OA = the hypotenuse = √(10² + 35²) = √(5²(2² + 7²)) = 5 √(4 + 49) = 5√53

Therefore, the distance between A and the initial point is 5√53 m.

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