Math, asked by pankoobhaiya, 3 months ago

A person started his journey in the morning. At 11 A.M, he covered 3/8 th of his journey and on the same day at 4 : 30 P.M, he covered 5/6 th of his journey. At what time did he start his journey?​

Answers

Answered by mahamahmood95
0

Step-by-step explanation:

he covered 5/6part -3/8 part of the distance

in 4:30 -11:00

= 5/6-3/8

=40-18/48

=22/48

=11/24 parts of the distance

in 5:30 hours

=5½ =11/2hours

the distance covered at 11:pm

11/24 parts of the distance=11/2

distance= 11/2*24/11

Distance=12 hours

3/8*12hours=time

time= 36/8 hours

time= 9/2 hours

time= 4:30

he started his journey at

=11:30 - 4:30

=6:30 a.m

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