Question

A person started walking towards the east and covered a distance of 9 m and turned towards the north and covered a distance of 30 m. Then, he turned towards the west and covered 2 m and finally turned towards the south and walked a distance of 6 m. The distance between the initial and final positions of the person is: [1​

Answer 1

Answer:

distance = total path covered

distance =9m+30m+2m+6m

distance=47m

Answer 2

Given:

A person walks:

east and covered a distance of 9 m and turned towards the north and covered a distance of 30 m. Then, he turned towards the west and covered a distance of 2 m and finally turned towards the south and walked a distance of 6 m.

To find: distance between initial and final positions of the person.

Solution:

Draw the required diagram.

Consider $\[\Delta ABC\]$ in the diagram, apply pythagoras theorem to find the distance between initial and final position of the person.

$\[\begin{array}{l}A{B^2} = A{C^2} + B{C^2}\\ \Rightarrow A{C^2} = {7^2} + {24^2}\\ \Rightarrow A{C^2} = 49 + 576\end{array}\]$

$\[\begin{array}{l} \Rightarrow A{C^2} = 625\\ \Rightarrow AC = 25m\end{array}\]$

Hence, the distance between the initial and final positions of the person is 25m.