Question

A person starting from rest and travelling in a staraight line attains a velocity of 9km/h in 10 seconds by accelerating uniformly. The distance travelled by the person in this time interval is​

Answer 1

Answer:

Explanation:

45m/s

Answer 2

Answer:

Hoi!!

For the first part, finding the acceleration

u = 0km/h = 0m/s *

v = 9km/h = 2.5m/s

t= 10sec

$\ \frac{v - u}{t} = \frac{2.5 - 0}{10} = 0.25m {s}^{ - 2}$

a = 0.25m/s²

For the second part, finding the distance travelled

$s = ut + \frac{1}{2} a {t}^{2} = 0 \times 10 + \frac{1}{2} 0.25 \times {10}^{2} = 12.5m$

s = 12.5 m

Explanation:

* conversion into SI units for ease of working on the question multipled by

$\frac{5}{18} ( \frac{1000}{60 \times60} )$

Hope it was helpful.