A person starts from a point A and travels 6 km westwards to B and then turns right and trvels half of that idstance to reach C. He again turns right and travels 5
2
times the distance he covered between A and B and D. The shortest distance between the starting point and the last position is (in km).
Answers
Given : A person starts from a point A and travels 6 km Westwards to B and then turns Right and travels half of that distance to reach C.
He again turns right and travels (2/9) the distance he covered between A and B and reaches his destination D.
To Find : The shortest distance between the starting point and the destination is:
Solution:
N
W E
S
(2/9)(6 + 3) = 2
C ---- -D
|
6/2 = 3 km
|
B ------6 km -----------A
WEST = 6 km
Then Right Means North = (6/2) = 3 km
Again Right Means East = (2/9)(6 + 3) = 2 km = - 2 km West
Total North = 3 km
Total West = 6 -2 = 4 km
From starting point 4 km West and 3 km North
The shortest distance between the starting point and the last position is (in km). = √3² + 4² = 5 km
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