A person starts from a point P and walks 1 km
along a straight line and then turns to his
right and walks straight for 2 km. After that,
he turns to his left and walks for 3 km to
reach a point Q. What is the straight line
distance of the point Q from the point P ?
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1
Answer:
Correct option is
B
15 km
The movement of the person are as shown in fig.
Clearly AB = 3 km
BC=3AB=(3×3)KM=9KM
CD=5AB=(5×3)KM=15KM
Draw AE ⊥ CD.
Then CE = AB = 3 km and
AE = BC = 9Km
DE = (CD-CE)=(15-3)Km = 12 Km.
In Δ AED, AD
2
=AE
2
+DE
2
= AD=(
9
2
+(12)
2
)km=15km
∴ Required distance = AD = 15 Km.
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