Question

A person starts from point X at 6:00 am. He reaches point Y and Z at 7:00 am and 9:00 am respectively. When he takes 2 hours to return to point X and the distance XY and YZ is 30 km and 60 km respectively, calculate the average speed of the person

Answer 1

Answer:

at the first trip he took 3 hrs to travel 90 km

and at the second trip he took 2 hrs to travel 90 km then average speed is

(speed of first trip + speed of second trip) /2

therefore ans is 37.5 kmph