Question

a person starts its walkfrom home toward east after 4 km he takes a right turn walk 4km again then takes the right turn and moves 6 km his dispacement during walk is ______
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Answer 1

Answer:

the displacement will be 2 km

Answer 2

Path covered by the person.

$\setlength{ \unitlength}{1cm} \thicklines \begin{picture}(10,10) \put(0,0){\framebox{ \sf home}} \put(1,0.1){ \vector(1,0){2}} \put(1.5,0.2){ \sf 4km} \put(3,0.2){ \vector(0,1){2}} \put(3.2,1){ \sf 6km} \put(1,0.1){ \vector(1,1){1.9}} \put(0.4,1.5){ \sf displacement} \end{picture}$

The displacement can be found by using the Pythagoras theorem.

here, The longest side is the hypotenuse ( displacement ) and the other two sides are base and perpendicular which measure 4 km and 6 km respectively.

So,

Displacement² = Base² + Perpendicular²

=> Displacement = √(4² + 6²)

=> Displacement = √(16 + 36)

=> Displacement = 2√13 km