A person starts writing all 4 digits numbers.How many times had he written the digit 2?
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Answer:
3168 times he wrote digit 2
Step-by-step explanation:
Total Amount of 4 digital numbers
= (9(0 is useless))*(10)*(10)*(10)
= 9000 numbers
Total Amount of 4 digital numbers (without 2)
= (8(0,2 not include)) *(9)*(9)*(9)
= 5832
No. of time he wrote digit 2
= Total Amount of 4 digital numbers- Total Amount of 4 digital numbers without 2
= 9000-5832
= 3168 ,,
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