A person stepped out of his house and started walking. He moved 40m due East then 10m due South then 20m due East then 20m due South and then he finally walked out 6000cm due west. Now in which direction and how much distance does he moves. So that his displacement will be zero? PLS ANSWER IF U KNOWS. I WILL MARK BRAINLIEST. SURE
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Answered by
1
Answer:
total distance 50m +40m+20m
distance =110m
displacement = OA
OC-CL=OL 50-20 =30m
AL =40m
\begin{lgathered}{h}^{2} = {p}^{2} + {b}^{2} \\ oa {}^{2} = al {}^{2} + ol {}^{2} \\ oa {}^{2} = 30 {}^{2} + 40 {}^{2} \\ oa {}^{2} = 900 + 1600 \\ oa {}^{2} = 2500 \\ oa \: = 50 \\ oa = 50m\end{lgathered}
h
2
=p
2
+b
2
oa
2
=al
2
+ol
2
oa
2
=30
2
+40
2
oa
2
=900+1600
oa
2
=2500
oa=50
oa=50m
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