Question

A person suffering with myopia with far distance 5m what his focal length of his eye

Answer 1

Answer:

Answer:

Given :

Distance of far point x = 5m

Focal length of the corrective lens to view distant objects correctly: f = -x

= -5 m

Power of the lens = 1/f

= 1/(-5)

-0. 2 D

HOPE IT IS HELPFUL...

Answer 2

Answer⤵️

When the object is at infinity the virtual image should form at 5m

$u = \infty \\ v = - 5m \\ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\ \frac{1}{f} = \frac{1}{ - 5} - \frac{1}{ \infty } \\ f = - 5 \\ \\ \text{now \: power \: p = } \: \frac{1}{f} = \frac{1}{ - 5} = - 0.2d$

Hope this helps!