A person swings a stone tied to a string in a horizontal circular path.How much work does hd do?
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When the person rotates the stone, he applies centripetal force radially inwards to keep the stone in a circular path.
However, the velocity of the stone is tangential to the circular path.
Thus, the angle between the force applied and instantaneous displacement of the stone is 90°.
W = FS cos 90
= FS × 0
= 0
So the work done in rotating the stone in a horizontal circular path is 0.
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Here's your answer...
When the person rotates the stone, he applies centripetal force radially inwards to keep the stone in a circular path.
However, the velocity of the stone is tangential to the circular path.
Thus, the angle between the force applied and instantaneous displacement of the stone is 90°.
W = FS cos 90
= FS × 0
= 0
So the work done in rotating the stone in a horizontal circular path is 0.
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
ssanjana9:
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