Question

A person takes a loan of RS. 20000 for his house repair work at 10% simple interest for 2 years. The amount to be returned including interest after 2 years is

Answer 1

AnswEr :

$\bold{Given} \begin{cases} \underline{ \footnotesize\sf{ \star \: \: Find\: Amount\:with \: Simple\: Interest}} \\ \sf{Principal=Rs. 20000} \\ \sf{Rate=10\% \: p.a.} \\ \sf{Time=2\: Yr. }\end{cases}$

• According to the Question Now :

$\leadsto\sf Simple \:Interest=\dfrac{PRT}{100}$

$\leadsto\sf Simple \:Interest=\dfrac{200\cancel{00} \times 10 \times 2}{ \cancel{100}}$

$\leadsto\sf Simple \:Interest=200 \times 10 \times 2$

$\leadsto \boxed{\sf Simple \:Interest=Rs. \: 4000}$

_________________________________

⇒ Amount = Principal + Interest

⇒ Amount = Rs. 20,000 + Rs. 4,000

⇒ Amount = Rs. 24,000

⠀

∴ He have to Return Rs. 24,000 after 2 Yrs.

Answer 2

$\huge\tt{AnsweR}$

Question:

A person takes a loan of RS. 20000 for his house repair work at 10% simple interest for 2 years.

The amount to be returned including interest after 2 years is.

Answer:

$\tt SI = \frac{P × R × T }{100} \\ </p><p>\tt SI = \frac{20000 × 10 × 2 }{100} \\ </p><p>\tt SI = 200 × 10 × 2 \\ </p><p>\tt SI = 400 \\ </p><p></p><h2> \tt Amount = Principal + Interest \\ </h2><p>\tt A = 20000 + 4000 \\ </p><p>\tt A = 24000$