Question

A person takes T1 second on the stationary
escalator to cover some distance. The person
takes T2 second in the moving escalator to cover
same distance by same velocity. If person is at
rest on the escalator then time taken by him to
cover same distance is
(1) T2T1 / T2-T1
(2)T₂T1/T2+ T1
(3)T2T1/T1-T2
​

Answer 1

Answer:

Let the length of escalator is L.

Then, velocity of man = distance/time taken = L/T₁

Velocity of man with respect to escalator = L/T₂

so, velocity of escalator with respect to man = -L/T₂

We know,

velocity of escalator = velocity of escalator with respect to man + velocity of man

L/T = -L/T₂ + L/T₁ = L/(1/T₁ - 1/T₂)

T = T₁T₂/(T₂ - T₁)

Answer 2

Answer:

Answer of this question is given in the above image