A person threw a ball of mass 100 g with a speed of 20 m/sec. It came to rest after 5 seconds. Find average force applied by the person.
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1
Force= m * a
F= 0.1 kg * 20/5 m/sec square
F=0.1 *4
F= 0.4 newton
Answered by
1
Answer:
A person threw ball of mass 100 g Speed 20m/sec it came to rest after 5 second.
a=(v−u)/t⇒
a=(0−20)/0.01=−2000m/s
2
F=m×a⇒
F=0.1×2000=200 N.
The hand apply equal and opposite force of 200 N.
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