A person threw a standard dice 3 times. He obtained
two distinct odd prime numbers in two throws and an
even number which is not a factor of 18 in the third
throw. The sum of all the numbers on the opposite
faces of numbers obtained in the three throws is
(1) 9 (2) 12
(3) 10 (4) 15
Answers
Answered by
4
HELLO MATE ____❤️
The sum of a face with its opposite face is always 7.
So we have that the opposite faces of 3, 5 and 4 are 4, 2 and 3 respectively.
From there we have the answer: 4+2+3=9.
So the correct answer for this question is option A: 9
(1) 9 ✔️✔️
(2) 12
(3) 10
(4) 15
❤️BRAINLIEST PLS❤️
Similar questions