A person threw a standard dice 3 times. He obtained two distinct odd prime numbers in two throws and an even number which is not a factor of 18 in the third throw. The sum of all the numbers on the opposite faces of numbers obtained in the three throws is
a)9 b)12
c)10. d)15
ramkumar200180:
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Answered by
20
A person threw a standard dice 3 times .He obtained two distinct odd prime numbers in two ...............three throws is. Answer (1.)9
Answered by
34
Thank you for asking this question. Here is your answer:
The sum of a face with its opposite face is always 7.
So we have that the opposite faces of 3, 5 and 4 are 4, 2 and 3 respectively.
From there we have the answer: 4+2+3=9.
So the correct answer for this question is option A: 9
If there is any confusion please leave a comment below.
2 to 5
3 to 4
the sum of each pair= 7
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