Math, asked by Rohit96369, 1 year ago

A person threw a standard dice 3 times. He obtained two distinct odd prime numbers in two throws and an even number which is not a factor of 18 in the third throw. The sum of all the numbers on the opposite faces of numbers obtained in the three throws is

a)9 b)12
c)10. d)15


ramkumar200180: What is answer

Answers

Answered by eshajodhan
20

A person threw a standard dice 3 times .He obtained two distinct odd prime numbers in two ...............three throws is. Answer (1.)9


logicalthinker: how.
logicalthinker: can you send the steps
naman861: give reasons
Answered by Shaizakincsem
34

Thank you for asking this question. Here is your answer:

The sum of a face with its opposite face is always 7.

So we have that the opposite faces of 3, 5 and 4 are 4, 2 and 3 respectively.

From there we have the answer: 4+2+3=9.

So the correct answer for this question is option A: 9

If there is any confusion please leave a comment below.



jashandeep2003: thank u very much
khrithik2004ov3f1m: Why should it be 7 only
Shaizakincsem: 1 to 6

2 to 5

3 to 4
the sum of each pair= 7
ayazalam212: It has said that two odd prime no. Then why are you taking even no.
sai1233: how did you get the no 3 and 5
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