a person throws a ball of mass 100 gram with a speed of 20meter per second . It came to rest after 5 second . Find the average force applied by the person
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Answered by
5
Answer:
0.4 Newton will be the required force.
Explanation:
According to the Question
Mass of ball,m = 100g = 0.1 kg
• Initial velocity,u = 20m/s Final velocity ,v = 0m/s
Time taken t = 5s
we have to calculate the Average Force applied by the Person.
For calculating the force applied, we will apply here formula.
Force is calculated by the product of mass and acceleration.
And, also acceleration is defined as the rate of change in velocity at per unit time.
F = ma
→→
Favg = mˇ-u
by substituting the value we get
we get
Favg = 0.1 x 0 - 20 LO 5
Favg
=0.1 ×-20 5
Favg = 0.1 × (-4)
Favg = 0.4N
Here, negative sign shows that the force is acting in opposite direction of moticon.
Answered by
4
Answer:
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