Question

A person throws a ball upward into the air with an initial velocity of 15 m/s. The ball goes up to height H and then goes down back into the hand of person given g=9.8 m/s 2 What is the value of h?

Answer 1

Answer:

sorry not sure

Explanation:

less than 100m

Answer 2

Explanation:

Given to you that the initial velocity of the ball is

15 m/s

Now when the ball reaches to its maximum height its final velocity becomes zero.

Also g =9.8 m/s^2

Applying the equation v^2=u^2-2as

where a=g and s=h

Therefore

=> 0=(15)^2-2(9.8)h

=> 225=19.6 h

=> h= 225/19.6

=>h= 11.4 m (Ans)