Question

A person throws a ball with the speed of 150kmph what should be the force applied to the ball so that the ball covers a distance of 60 yards in the opposite direction​

Answer 1

Answer:

Horizontal Distance, R = 63m

Velocity required, Vf = (9.8[g] x 63[R])^1/2 = 24.85 m/s (considering projection angle to be 45 degree)

Ball avg. mass, M = 0.16kg

Avg contact time, t = 0.002s

initial Horizontal Velocity of ball, Vb = 143 x 5/18 = 39.72m/s

change in horizontal velocity, Vx = Vb + Vf.cos45 = 57.3m/s

change in vertical velocity, Vy = Vf.sin45 = 17.57m/s

Total change in velocity, V = (Vx^2 + Vy^2)^1/2 = 59.93m/s

Total Force applied = M.V/t = 0.16 x 59.93/0.002 = 4794.4 N

Therefore, Force equivalent to 4.8 x 10^3 Newtons is to be applied