Question

A person throws a stone with a velocity 10m/s at angle tan 0= 3/4 to horizontal
from a point at a distance 8m from the wall. The stone just passes over the
wall. The height of the wall is (g= 10m/s2)​

Answer 1

Answer:

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Answer 2

Answer:

1.8m

Explanation:

tanø=3/4 → sinø=3/5( 3,4,5 Pythagoras theorem)

v=10m/s

H=u²sin²ø/2g

H=100*9/25*2*10

H=9/5= 1.8m