Question

A person traveling on a scooter at 43.2 km/h applies the brakes, giving a deceleration of 6.0 m/s2. How far will it go without stopping

Answer 1

Answer:

12 metres

Answer in attachment

Answer 2

Answer:

Explanation:

Given:-

Initial velocity of a scooter, u = 43.2km/hr = 43.2 x 5/18 = 12 m/s

final velocity of a scooter, = v = 0m/s [Because brakes are applied]

Acceleration by the scooter, a = -6.0m/s²

To Find :-

Distance Traveled by the scooter, s = ? ??

Formula to be used :-

3rd equation of motion i.e v² - u²= 2as

Solution :-

s = v² - u²/2a

s = 0² - 12²/2x - 6

S = 12m

Hence, distance travelled before stopping is 12m.