Question

A person travelled a distance 3 km along a straight line in the North. Then he travelled 2 km in West
direction and then 5 km in South direction. The magnitude of the displacement of this person would be
velocity V, and the rest half with velocity V2, its average

plz help I am in std 11​

Answer 1

Answer:

IA person walked 3 km in north, 2km west and 5 km in South. Then, the map becomes like:

Then now we have .

P=5–3=2km b=2km

So H^2=P^2+B^2,

H^2= 4+4

H^2=8

Or H=√8

The displacement travelled by person is 2√2 km or 2.82km