Question

a person travelled a distance of 610 km in 9 hours . he travelled the first phase at a speed of 40kmph and the rest at 90kmph. the distance travelled during the first phase is​

Answer 1

Explanation:
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 - x) hr

Distance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9-x) = 61
=> 5x = 20
=> x = 4

So distance traveled on foot = 4(4) = 16 km



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