Question

A person travelling at 43.2 kmph applies brakes giving a deceleration of 4 m/s2 to his car. Find
the distance travelled by the car before it comes to rest.

Answer 1

Explanation:

given :-

u = 43.2km/hr.

= 43.2 x 5/18

= 1/12

v = 0

a = -4m/s²

s = ?

so on applying third equation of motion

v² = u² + 2as

0² = 1/12 + 2 x -4 x s

0 = 1/12 - 8s

0 = 1 - 8s ( on cross multiplying of 12 x 0)

-1 = -8s

s = 1/8 m or 0.125 m

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