Question

A person travelling at 43 2Km/h applies breake a deceleration of 6.0m/s2 to his scooter. How far will it travel before stopping Concept of Physics - 1 , HC VERMA , Chapter "Rest and Motion : Kinematics

Answer 1

Correct Question

A person travelling at 43.2Km/h applies breake a deceleration of 6.0m/s2 to his scooter. How far will it travel before stopping??

Solution

Given

• Initial Velocity (u) = 43.2 Km/h
• Acceleration (a) = - 6 m/s²

To finD

• Distance covered before stopping

Here,

• Acceleration is along negative x axis i.e.,it's retardation » a = - 6 m/s²
• Final Velocity would be zero as the breaks have been applied
• Initial Velocity = 43.2 × 5/18 = 2.4 × 5 = 12 m/s

From v² - u² = 2as,

0² - 12² = 2(-6)s

» - 144 = - 12s

» s = 144/12

» s = 12 m

The scooter covers 12m before come to rest