Question

A person travelling by a car moving at 100 km h−1 finds that his wristwatch agrees with the clock on a tower A. By what amount will his wristwatch lag or lead the clock on another tower B, 1000 km (in the earth's frame) from the tower A when the car reaches there?

Answer 1

Answer:

don't know if this requires in depth or just an overview of Newtonian physics so here's both

firstly applying Newtonian physics

v=100

s=1000

t=v/t

so 10 hours.

now for relativistic approach

the time for the wrist watch will be slower than than the clock. let the time for watch be t2 and the time for clock be 10 hours reach ( from above calculation).

let's use the formula

t2=

$t1 \div \sqrt{1 - ({v}^{2} \div {c}^{2} )}$

that will be

$10 \div \sqrt{1 - (10000 \div {c}^{2} )}$