A person travelling on a bus noted the timings and the corresponding distances as indicated on the km stones. time-distance 8.00 AM-10km 8.15 AM-20km 8.30 AM-30km 8.45 AM-40km 9.00 AM-50km
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Answered by
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average speed between 8.00 AM and 8.15 AM : 10km/(1/4 hr) = 40 kmph
average speed between 8:!5 and 8:30 : 10km/(1/4) = 40 kmph
avg speed between 8:30 and 8:45 : 10/(1/4) = 40 kmph
avg speed between 8:45 and 9:00 : 10/(1/4) = 40 kmph
so the bus is traveling at uniform speed. The average speed from 8:00 AM to 9:00 PM = 40 kmph
Total distance traveled = 40 km
average speed between 8:!5 and 8:30 : 10km/(1/4) = 40 kmph
avg speed between 8:30 and 8:45 : 10/(1/4) = 40 kmph
avg speed between 8:45 and 9:00 : 10/(1/4) = 40 kmph
so the bus is traveling at uniform speed. The average speed from 8:00 AM to 9:00 PM = 40 kmph
Total distance traveled = 40 km
Answered by
2
Answer:
Average speed between 8:00 AM and 8:15 AM =10Km /(1/4 hr)=40 Kmph
Average speed between 8:15 AM and 8:30 AM =10Km /(1/4 hr)=40 Kmph
Average speed between 8:30 AM and 8:45 AM= 10Km /(1/4 hr)=40 Kmph
Average speed between 8:45 AM and 9:00 AM= 10Km /(1/4 hr)=40 Kmph
So,the bus is traveling at uniform speed. The average speed from 8:00 AM to 9:00 AM= 40Kmph
Total distance travelled = 40Km
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