Question

A person travelling on a scooter at 43.2 km/h giving a deceleration of 6m/s² to his scooter. How far will it travel before stopping (v=0

Answer 1

Given :-

• A person travelling on a scooter at 43.2 km/h giving a deceleration of 6m/s² to his scooter.

To find :-

• How far will it travel before stopping ?

Solution :-

• Initial velocity = 43.2km/h

• Acceleration = - 6m/s²

• Final velocity = 0

→ Final velocity = 43.2 km/h

→ v = 12 m/s

• According to third equation of motion

→ v² = u² + 2as

Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " s " is distance.

• According to question

→ (0)² = (12)² + 2 × (-6) × s

→ 0 = 144 - 12s

→ 12s = 144

→ s = 144/12

→ s = 12 m

Hence,

• Distance travelled before stopping is 12m

More to know :-

• s = ut + ½ at² (second equation of motion)
• v = u + at (first equation of motion)
• Acceleration is the rate of change in velocity.
• Acceleration in negative is known as retardation

Answer 2

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: Question :- \: \star}}}}}$

A person travelling on a scooter at 43.2 km/h giving a deceleration of 6m/s² to his scooter. How far will it travel before stopping (v=0)

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

Distance travelled before stopping is 12m

$\Large{\underline{\underline{\bf{Given:-}}}}$

Initial velocity = 43.2km/h

Acceleration = - 6m/s²

$\Large{\underline{\underline{\bf{Find:-}}}}$

Distance travelled before stopping ?

Here we go yo ^^"

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

❥ Final velocity = 43.2 km/h

❥ v = 12 m/s

Applying Third law of motion

↠ v² = u² + 2as

" v " = final velocity

" u " = initial velocity

" a " = acceleration

" s " = distance

❥ (0)² = (12)² + 2 × (-6) × s

❥ 0 = 144 - 12s

❥ 12s = 144

❥ s = 144/12

❥ s = 12 m

$\mathfrak{\huge{\purple{\underline{\underline{Hence}}}}}$

S = 12m

$\Large{\underline{\underline{\bf{Additional Information:-}}}}$

❥ In the first law, an object will not change its motion unless a force acts on it.

❥ In the second law, the force on an object is equal to its mass times its acceleration.

❥ In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

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