Question

A person travels 150 km from A and B in 3 hours and 20 minutes and returns to the place in 4 hours and 10 minutes. If Y1 is the average speed of the entire trip, then the average speed of the trip from A to B exceeds Y1 by ​

Answer 1

Answer:

5 km/hr

Explanation:

Average speed = Total distance/ Total time.

Total distance = 300km [ A to B and then B to A ]

Total time = 3hrs 20min + 4hrs 10min = 7hrs 30min

Here average speed is Y1.

               Y1 = Total distance/ Total time.

                   = 150 + 150 / 7.5

                   = 40km/hr

Speed of trip from A to B,

Time = 3*60 + 20 = 200min

                           = $\frac{200}{60}$ hrs

Speed = $\frac{150}{200/60}$

          = 45km/hr

So speed from A to B exceeds Y1 by 5km/hr