a person travels a distance at a speed of 12kmph and returns at 9kmph the total time taken by him is 3hrs 30 mins . find distance travelled one way
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Answer:
18kms
Step-by-step explanation:
let the total distance be x
ATQ speed, a = 12kmph ; b =9kmph
total time =3 hour 30 min. = 7/2
Average speed = 2ab/(a+b)
=2*12*9/(12+9)
=72/9
speed = distance / time
72/9 = 7 / 2
total distance x = 36kms
Hence distance travelled one way = 36/2 = 18kms
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