A person travels a distance of 6.0m towards east, then turns left and travels 8.0m towards north. (i) What is the total distance travelled by the person? (ii) What is the magnitude and direction of his displacement?
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A man walks 8 m towards East then 6 m North. What is his magnitude of displacement?
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It depends upon where he is on the Earth when he starts (or which astronomical body he starts on, and whether or not it is spherical!)
His displacement would be about 6m if he starts at a point 6m South of the North Pole, or if he starts on the equator of an asteroid with a diameter of about 4m (12/pi), or if he is in Antarctica starting at about 1.27 m (or 4/pi) North of the South Pole (and therefore walks 8m Eastard in a complete circle before going North).
Oh, if this was a “flat Earth” question (or if a Mercator map is a good enough approximation), then the answer is sqrt( 8^2 + 6^2).
However, if it is on a curved surface, then you must compute the chord (or drill a tunnel between the two points) to obtain a precise answer.
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