A PERSON TRAVELS A DISTANCE X=20t+2At^2 , WHERE A IS A CONSTANT . THE ACCELERATION OF THE PERSON IS :
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Ans. is 4A ... solution is in the pic ^_^
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Dhinu:
to ... acceleration ki value pata chal jaayegi
haan sahi h ... ese hi hoga
wese... sorry sorry sorry..... wahi firse yahaan network problem
:)
you're welcome soooooooooo much! ^_^
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