Question

a person travels along a straight road for the first half time with a velocity v¹ and the next half time with a velocity v². The mean velocity V of man is? ​

Answer 1

Answer:

• Mean velocity = $\frac{v_1 +v_2}{2}$

Given:

• First half time with velocity travel = $v_1$
• Next half time with a velocity = $v_2$

To Find:

• Mean velocity V of man is = ?

Solution:

For the first half time

where,

• t = time
• v_1 = Velocity
• s_1 = distance

As we know that,

$\sf\large{ Distance = speed \times time}$

•s_1 = v_1 × t

For the second half time

where,

• t = time
• v_2 = velocity
• s_2 = distance

As we know that,

$\sf\large{ Distance = speed \times time}$

•s_2=v_2 × t

Now,after knowing the both half times then find the mean velocity.

As we know,

$\: \: \sf \: mean \: velocity = \frac{s1 + s2}{t + t}$

Now,put the values we find

$\: \: \sf \: mean \: velocity \: = \frac{v1 \cancel t + v2 \cancel t}{2 \cancel t} \\ \\ \: \sf \therefore \: \: mean \: velocity \: = \frac{v1 + v2}{2}$

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Answer 2

Answer:

sry

Step-by-step explanation:

no anwer...

sorryyy