A person travels from A to B at 75kmph in a car and in the return journey the speed is reduced by 15kmph.If the total time taken is four-half- hours then the distance in kms between A and B
Answers
Answered by
12
given s1=75kmph
reduced 15kmph s2 =60kmph
avg speed = 2xy/x+y
2×75×60/75+60
150×60/135
10×60/9
600/9
200/3
speed=200/3
time= 4.5hrs
speed=distance/time
distance=speed×time
distance=200/3×9/2
d=100×3=300kms is answer
reduced 15kmph s2 =60kmph
avg speed = 2xy/x+y
2×75×60/75+60
150×60/135
10×60/9
600/9
200/3
speed=200/3
time= 4.5hrs
speed=distance/time
distance=speed×time
distance=200/3×9/2
d=100×3=300kms is answer
dinah65:
answer given 150 in key
Similar questions