A person travels from a to b at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips?
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Speed of First travel From a to b = 40 km /hr
Increment of speed by 50 % =40 +50%of 40
=40+20
I.e 60
Average speed = 40+60/2
I.E 50km/hr
hope it will be useful
Increment of speed by 50 % =40 +50%of 40
=40+20
I.e 60
Average speed = 40+60/2
I.E 50km/hr
hope it will be useful
khushi291728:
how
See the method
there was an increment of speed by 50 percent
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