Question

A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ? 44 km/hour 46 km/hour 48 km/hour 50 km

Answer 1

Hey.

Here is the answer.

let the distance between P and Q is x km

Speed from P to Q = 40 kmph

so, time taken to go to Q = x/40 h

As, speed increased by 50% in return

so, speed back to P = 40+ 50% of 40

= 40+ 0.5×40 = 60 kmph

so, time taken in return = x/60 h

So, total distance travelled= 2x

total time taken = x/40 + x/60

= (3x+2x)/120

= 5x/120

= x/24 h

So, average speed for both the trips

= 2x / (x/24)

= 48 kmph

Thanks.